7(x+1)=4[3x-(7-x)]

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Solution for 7(x+1)=4[3x-(7-x)] equation:


Simplifying
7(x + 1) = 4[3x + -1(7 + -1x)]

Reorder the terms:
7(1 + x) = 4[3x + -1(7 + -1x)]
(1 * 7 + x * 7) = 4[3x + -1(7 + -1x)]
(7 + 7x) = 4[3x + -1(7 + -1x)]
7 + 7x = 4[3x + (7 * -1 + -1x * -1)]
7 + 7x = 4[3x + (-7 + 1x)]

Reorder the terms:
7 + 7x = 4[-7 + 3x + 1x]

Combine like terms: 3x + 1x = 4x
7 + 7x = 4[-7 + 4x]
7 + 7x = [-7 * 4 + 4x * 4]
7 + 7x = [-28 + 16x]

Solving
7 + 7x = -28 + 16x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16x' to each side of the equation.
7 + 7x + -16x = -28 + 16x + -16x

Combine like terms: 7x + -16x = -9x
7 + -9x = -28 + 16x + -16x

Combine like terms: 16x + -16x = 0
7 + -9x = -28 + 0
7 + -9x = -28

Add '-7' to each side of the equation.
7 + -7 + -9x = -28 + -7

Combine like terms: 7 + -7 = 0
0 + -9x = -28 + -7
-9x = -28 + -7

Combine like terms: -28 + -7 = -35
-9x = -35

Divide each side by '-9'.
x = 3.888888889

Simplifying
x = 3.888888889

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